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1 vote
Can u help me answer this I’m so stuck

Step by step pls
Also there’s one more question
0.004 recurring as a fraction in its simplest form

Can u help me answer this I’m so stuck Step by step pls Also there’s one more question-example-1
Can u help me answer this I’m so stuck Step by step pls Also there’s one more question-example-1
Can u help me answer this I’m so stuck Step by step pls Also there’s one more question-example-2
Can u help me answer this I’m so stuck Step by step pls Also there’s one more question-example-3
Can u help me answer this I’m so stuck Step by step pls Also there’s one more question-example-4
Can u help me answer this I’m so stuck Step by step pls Also there’s one more question-example-5
User Rplaurindo
by
4.3k points

1 Answer

4 votes

Answer:

I learned a great formula for repeating decimals.

OK! Let's get started. For each decimal spot that is recurring, it is put over a 9, rather than a 10.

In your case, 0.142 would be 142 over 3 9s.

142/999 cannot be simplified.

Therefore, 142/999 is our answer.

Since the repentant is over only one digit, we have to solve another way.

We can represent it as "x"

10x = 5.66.... - x = 0.56.....=5.1

9x = 51/10

51/10/9 = 51/90 = 17/30 as our answer.

We can solve this next one the same way:

100x = 3.44444 - x = 3.41

999x = 341/100

341/100/999 = 31/900 as our answer.

Now! 1.52 can be solved the same way.

In doing so, we achieve the answer 151/99 as our answer

This one can be done the same way as well. I'll give you the answer, but next time try to solve it for yourself!

179/495 is our answer.

Now, you asked for 0.004 as a fraction.

That is equivalent to 4/999 as our answer.

Note: This is because each 0 can be counted as a 9, increasing in order. (i.e., over 100 is over 99 over 1000 is over 999 over 10 9)

User Humayun
by
5.7k points
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