Question

Which is the equation of a circle with its center at (-4,2) and a radius of 4?

A. (x + 4y + (y - 2y = 16
B. (x + 4y + (y - 29 - 4
C. (x - 4)* + (y + 2y = 16
D. (x-4) + (y + 2y = 4

Answer 1

(x +4)^2 + (y-2)^2 = 16

Explanation:

We can write the equation for a circle with the formula

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

We know the center is at (-4,2) and the radius is 4

(x- -4)^2 + (y-2)^2 = 4^2

(x +4)^2 + (y-2)^2 = 16