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Find the center and radius of circle of x^2+y^=36

1 Answer

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Answer:

The center is (0,0) and the radius is 6

Explanation:

The equation for a circle can be written in the form

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

x^2+y^2=36

can be written as

(x-0)^2+(y-0)^2=6^2

The center is (0,0) and the radius is 6

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