Question

How much energy is stored in the spring of a dart gun that has a force constant of 20nm and compressed .25m

Answer 1

Potential energy stored in the spring is given as

U = 0.625 J

Step-by-step explanation:

As we know that the potential energy stored in the spring is given as

`U = (1)/(2)kx^2`

so we have

K = 20 N/m

also the spring is compressed by

x = 0.25 m

so we have

`U = (1)/(2)(20)(0.25)^2`

`U = 0.625 J`