Question

Use the Quadratic Formula to solve

x²-13x+42=0

Answer 1

x1=7,

x2=6

Explanation:

x²-13x+42=0

a=1, b=-13, c=42

x1,2=(-b+-sqrt(b^2-4ac)) /2a

x1,2=(-(-13)+-sqrt((-13)^2-4*1*42))/2*1

x1,2=(13+-sqrt (169-168))/2

x1,2=(13+-sqrt(1))/2

x1,2=(13+-1)/2

x1=(13+1)/2, x2=(13-1)/2

x1=14/2, x2=12/2

x1=7, x2 =6