Question

Someone help me please. I need my work submitted by 4:00

Answer 1

`B.\ (-1.4z+0.4)* 40 \\\\D.\ (8z-4)(-7)`

Explanation:

Given the expression:

`-56z+28`

#We introduce a bracket and a common divisor:

Since 7 is a divisor of both numbers, we rewrite the expression as:

`-56z+58=-7(8z-4)\\\\=(8z-4)(-7)`

#We then introduce a second common divisor, 40:

`-56z+28=(1)/(40)*-56z+28* (1)/(40)\\\\=40(-1.4z+0.7)`

Hence, the expression can be rewritten as 40(-1.4z+0.4) and (8z-4)(-7)