Question

Sonya found that x = StartFraction negative 4 Over 3 EndFraction is one solution of (6x + 4)2 = . The other solution is x = .

Answer 1

One solution of (6x + 4)^2 = 16

The other solution is x = 0

Answer 2

The other solution is x = 0.

Explanation:

Let the value of (?) is C.

It the given equation is
`(6x+4)^(2)` = C .

It can be written as
`(6x+4)^(2) - C`

Since x =
`(-4)/(3)` is the solution of the given equation, therefore will satisfies the given equation.

Put x =
`(-4)/(3)`

`( 6 ((-4)/(3)) + 4 )^(2) - C = 0`

`( -8 + 4 )^(2)` - C = 0

`- 4^(2)` - C = 0

C = 16

The given equation become

`(6x+4)^(2) + 16 = 0`

`6x + 4 = 4`

6x = 0

`6x + 4 = -4`

x =
`(-4)/(3)`

The other solution is x = 0.