Question

Can someone help me with number 15

Answer 1

Explanation:

We will evaluate that with n values starting at 1 and ending at 5. To do that, simply replace the exponent n with 1, then 2, then 3, then 4, then 5.

`f(1)=((2)/(3))^1` so

`f(1)=(2)/(3)`

Then f(2):

`f(2)=((2)/(3))^2` simplifies a bit so maybe it's easier to see how to handle this:

`f(2)=((2^2)/(3^2))` so

`f(2)=(4)/(9)`

Then f(3):

`f(3)=((2^3)/(3^3))=(8)/(27)`

And f(4):

`f(4)=((2^4)/(3^4))=(16)/(81)`

And finally, f(5):

`f(5)=((2^5)/(3^5))=(32)/(243)`