Answer:
1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.
Step-by-step explanation:
![AgNO_3+Ca\rightarrow Ag+CaNO_3,\Delta H_(rxn)=-18.7 kJ/mol](https://img.qammunity.org/2021/formulas/chemistry/high-school/95samgunw4pnqnknbs12rls4pe0whw91np.png)
Mass of silver nitrate = 14.8 g
Moles of silver nitrate =
![(14.8 g)/(170 g/mol)=0.08706 mol](https://img.qammunity.org/2021/formulas/chemistry/high-school/uh6ir52jzbesekopzoiqyg09iubnwd6u73.png)
According to reaction, when 1 mole of silver nitrate reacts with 1 mole of calcium it gives 18.7 kJ of heat.
Then amount of heat released when 0.08706 moles of silver nitrate reacts :
![0.08706* 18.7 kJ=1.628 kJ\approx 1.63 kJ](https://img.qammunity.org/2021/formulas/chemistry/high-school/i47cfujfvzb5y82ljc7sb165h3df5eazr2.png)
1.63 kilo Joules of energy will be produced when 14.8 g of silver nitrate react.