Question

In ΔQRS, the measure of ∠S=90°, the measure of ∠R=31°, and QR = 46 feet. Find the length of SQ to the nearest tenth of a foot.

Answer 1

6.9

Explanation:

In ΔQRS, the measure of ∠S=90°, the measure of ∠R=31°, and QR = 46 feet. Find the length of SQ to the nearest tenth of a foot.

Answer 2

`SQ=23.7\ ft`

Explanation:

we know that

In the right triangle QRS

`sin(R)=(SQ)/(QR)` ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

`sin(31^o)=(SQ)/(46)`

solve for SQ

`SQ=(SQ)/(46)sin(31^o)=23.7\ ft`