Question

Find the first four terms of the sequence given by the following

An =54+3(n-1) n=1,2,3

Answer 1

Explanation:

An = 54 + 3(n-1)

n = 1 ; A1 = 54 + 3*(1-1) = 54 + 3*0 = 54 +0 = 54

n =2 ; A2 = 54 + 3*(2-1) = 54 + 3*1 = 54 + 3 = 57

n =3 ; A3 = 54 + 3*(3-1) = 54 + 3*2 = 54 + 6 = 60

n =4 ; A4 = 54 + 3*(4-1) = 54 + 3*3 = 54 + 9 = 63