Answer:
-3q(4q^2+q+3)
Explanation:
To solve this question we will have to open the bracket first
So let's solve
(-9q^3+(-8q)+(3q^2-q-6q^3)
Open the bracket first
(-9q^3-8q)+3q^2-q-6q^3
-9q^3-8q+3q^2-q-6q^3
Let's collect like terms
-9q^3-6q^3+3q^2-8q-q
-12q^3+3q^2-9q
We can actually factorise
-3q(4q^2+q+3)