Question

Lin and Jada each walk at a steady rate from school to the library. Lin can walk 13 miles in 5 hours, and Jada can walk 25 miles in 10 hours. They each leave school at 3:00 and walk 3 and 1/4 miles to the library. What time do they each arrive?

Answer 1

Explanation:

Given parameters:

Rate of walking by Lin = 13 miles in 5 hours

Rate of walking by Jada = 25 miles in 10 hours

Distance walked = 3.25 miles

Time of take off = 3:00

Solution:

The rate of their walking amounts to their speed;

Speed =
`(distance)/(time)`

Speed of Lin =
`(13)/(5)` = 2.6 miles/hr

Speed of Jada =
`(25)/(10)` = 2.5 miles/hr

To find the time; make it the subject of formula and solve for each person;

Time =
`(distance)/(speed)`

Time of Lin =
`(3.25)/(2.6)` = 1.25hr = 48 minutes

Time of Jada =
`(3.25)/(2.5)` = 1.3hr = 47 minutes

Time for each to arrive;

Lin = 3.00 + 1.25hr = 4:25

Jada = 3.00 + 1.30hr = 4:30