Question

Math geometry question 4, Thanks if you help

Answer 1

JDK-right triangle. JD=13, DK=3

By the Pythagorean theorem

`13^2+3^2=JK^2\\JK=√(169+9) \\JK=√(178) \\`

JK≈13,34

Answer: the distance is 13 units

P.S. Hello from Russia

Answer 2

The distance between two points J and K is 13 unit (approx)

Explanation:

Given,

Two points are J(3,0) and k(6,-13).

To find the distance between J and K.

Formula

The distance between two points (
`x_(1) ,y_(1)`) and (
`x_(2) ,y_(2)`) is
`\sqrt{(x_(2)-x_(1) ) ^(2)+(y_(2)-y_(1) ) ^(2) }`

Now,

Putting,
`x_(1) = 3, y_(1)=0, x_(2)=6, y_(2)=-13` we get,

JK =
`\sqrt{(6-3)^(2) +(-13-0)^(2) }`

=
`√(178)` unit = 13.34 unit (approx)