Question

A cell membrane is 0,0000005 m thick and has an electric potential difference between its surfaces of 0,10 V. What is the electric field within the membrane?

Answer 1

Electric field in the membrane is given as

`E = 2 * 10^5 V/m`

Step-by-step explanation:

As we know that electric field in a region is related to its potential difference given by the formula

`E = (\Delta V)/(\Delta x)`

here we know that

`\Delta V = 0.10 V`

`\Delta x = 0.0000005 m`

so we have

`E = (0.10)/(0.0000005)`

`E = 2 * 10^5 V/m`