Question

How many molecules of carbon monoxide gas can be produced from 395 grams of oxygen gas ?

Answer 1

The answer for the following problem is mentioned below.

• Therefore 148.125 × 10^-23 molecules of the cabon monoxide gas is produced.

Step-by-step explanation:

Given:

mass of the oxygen gas = 395 grams

We know;

For the production of the carbon monoxide;

The equation is,

Before balancing the equation;

C +
`O_(2)` → CO

After balancing the equation;

2 C +
`O_(2)` → 2 CO

where,

C = carbon molecule

O = oxygen molecule

CO = carbon monoxide

For the equation,

32 grams of oxygen gas → 2 × 6.023 × 10^-23 molecules

395 grams of oxygen gas → ?

=
`(2*6.023*10^(-23)* 395)/(32)`

= 148.125 × 10^-23 molecules of the carbon monoxide

Therefore 148.125 × 10^-23 molecules of the cabon monoxide gas is produced.