Question

What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)?

y=-1x +33
y=-3x + 36
y = 4x - 16
y = 4x + 16

Answer 1

The answer is letter D
y=4x+16

Answer 2

y = 4x + 16

Explanation:

y - 1 = 4(x + 3)

Has a slope of 4

y = 4x + c

32 = 4(4) + c

32 - 16 = c

c = 16

y = 4x + 16