Question

How many moles of NaCl are in 2,719 mL of a 6.32 M solution?

Answer 1

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

Step-by-step explanation:

`Molarity=\frac{\text{Moles of substance}}{\text{Volume of solution in L}}`

We have:

Molarity of the NaCl solution = 6.32 M

Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L

1 mL = 0.001 L

Let the moles of NaCl be n.

`6.32 M=(n)/(2.719 L)`

`n=6.32M* 2.719 L=17.18 mol`

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.