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Find the equation for the linear function that passes through the points (-4,-2)and(4,0)Answers must use whole numbers and/or fractions, not decimals

User Nrc
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1 Answer

5 votes

Answer:


y=-(1)/(4) x+1

Explanation:

Since they give you two points on the lane (-4,2) and (4,0), the line can be determined by using them to find:

1) the slope of the line via the formula:


slope=(y_2-y_1)/(x_2-x_1) =((0-2))/(4--4) =(-2)/(8) =-(1)/(4)

2) the line's y-intercept (b) requiring that one of the points satisfies the general equation of the line with the slope found above:


y=m\,x+b\\y=-(1)/(4) x+b\\

For example using point (4,0) in the equation above:


y=-(1)/(4) x+b\\0=-(1)/(4) (4)+b\\0=-1+b\\1=b

So the equation of the line through those points in slope intercept form is:


y=-(1)/(4) x+1

User NJones
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