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Let V be the vector space of all 2×2 matrices with real entries. Let H be the set of all 2×2 matrices with real entries that have trace 0. Is H a subspace of the vector space V?

User Regeirk
by
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2 Answers

3 votes

Answer:

tr(zA+B) = za+zb + a1+b1 = z(a+b)+(a1+b1) = 0+0 = 0 .

Explanation:

You need to show that given two matrices A,B such that tr(A) = tr(B) = 0 and a random number "z", tr(zA+B) = 0.


A = \left[\begin{array}{cc}a&x\\y&b\end{array}\right] \\B = \left[\begin{array}{cc}a1&x1\\y1&b1\end{array}\right] \\

By hypothesis a+b=0 and a1+b1 = 0

tr(zA+B) = za+zb + a1+b1 = z(a+b)+(a1+b1) = 0+0 = 0

Therefore H would be a subspace of V.

User Bhargav Jhaveri
by
6.1k points
5 votes

Answer:

H is not a subspace of v

Explanation:

Please see attachment

Let V be the vector space of all 2×2 matrices with real entries. Let H be the set-example-1
Let V be the vector space of all 2×2 matrices with real entries. Let H be the set-example-2
User Keith Otto
by
7.3k points
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