Question

The length of a rectangle is 10 inches longer than the width. The perimeter is 56 inches. Find the length and the width of the rectangle

Answer 1

`Length=19\,inches\\\\Width=9\,inches`

Explanation:

Let, the length of the rectangle be 'L',

Width of the rectangle be 'W'

`L=(W+10)\,inches`

Perimeter of the rectangle=
`56\,inches`

Perimeter of the rectangle=
`2(Length+Width)`

`56=2(W+10+W)\\\\(56)/(2) =W+10+W\\\\28=2W+10\\\\28-10=2W\\\\18=2W\\\\W=(18)/(2)\\\\ W=9\,inches`

As,

`L=(W+10)\,inches`

`L=9+10\\\\L=19\,inches`

`Length=19\,inches\\\\Width=9\,inches`