Question

The proof for the product property of logarithms requires simplifying the expression logb(bx+y) to x + y. Which property is used to justify this step?

Answer 1

c. on edge

Explanation:

Answer 2

`log_bb^c=c`

Explanation:

We are given that

`log_bb^(x+y)=x+y`

We have to find the property which is used to justify this step.

We know that

`e^(x+y)=e^x\cdot e^y}`

Using the formula

`log_b(b^x\cdot b^y)}=log_bb^x+log_bb^y`

By using the formula

`log(m\cdot n)=log m+log n`

`log_bb^(x+y)=x+y`

By using the property

`log_bb^c=c`