Question

A sample of a gas in a rigid cylinder with a movable piston has a volume of a lamp then .2 L at STP. What is the volume of this gas at 202.6 kPa and 300 Calvin?

Answer 1

Answer: The new volume of the gas is 0.11 L

Step-by-step explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1,V_1\text{ and }T_1` are the initial pressure, volume and temperature of the gas

`P_2,V_2\text{ and }T_2` are the final pressure, volume and temperature of the gas

At STP:

The temperature at this condition is taken as 273 K and the pressure at this condition is taken as 1 atm or 101.3 kPa.

We are given:

`P_1=101.3kPa\\V_1=0.2L\\T_1=273K\\P_2=202.6kPa\\V_2=?\\T_2=300K`

Putting values in above equation, we get:

`(101.3kPa* 0.2L)/(273K)=(202.6kPa* V_2)/(300K)\\\\V_2=(101.3* 0.2* 300)/(273* 202.6)=0.11L`

Hence, the new volume of the gas is 0.11 L