Question

An airplane takes off 3000ft in front of a 75ft y'all building. At which angle of elevation must the plane take off in order to avoid hitting the building?

Answer 1

Airplane plane should take off at angle of elevation of 1.43°.

Explanation:

As given in the figure attached,

Distance of the building from the point of take off (BC) = 3000 ft

Height of the building (AB) = 75 feet

We have to calculate angle of elevation (θ) so that airplane doesn't hit the building.

tanθ =
`\frac{\text{Opposite side}}{\text{Adjacent side}}`

tanθ =
`(AB)/(BC)`

tanθ =
`(75)/(3000)`

θ =
`tan^(-1)(0.025)`

θ = 1.432° ≈ 1.43°

Therefore, airplane should take off at angle of elevation of 1.43° to avoid the accident.