Answer:
Yes, value of adults having exactly 1 credit card is significantly low.
Explanation:
We are given that 74% of randomly selected adults have a credit card. Assume that a group of five adults is randomly selected.
And we have to check that if the group of five adults includes exactly 1 with a credit card, is that value of 1 significantly low or not.
The above situation can be represented through Binomial distribution;

where, n = number of trials (samples) taken = 5 adults
r = number of success = exactly 1
p = probability of success which in our question is % of adults
having a credit card, i.e; 74%
LET X = Number of adults having a credit card
So, it means X ~

Now, Probability that the group of five adults includes exactly 1 with a credit card is given by = P(X = 1)
P(X = 1) =

=
= 0.0169
So, the probability that in a group of five adults, exactly 1 have a credit card is 0.0169 or 1.69%.
Now, for any probability value to be significantly low it must be less than 5% as it is considered very unusual or may be called it that the probability of happening of that event is very rare or low.
Since, here our probability is way less than 5% i.e. 1.69%. So we can conclude that the value of adults having exactly 1 credit card in a group of 5 is significantly very low.