Question

A sample of gas at 25°C has a volume of 11 L and exerts a pressure of 0.868 atm. How many moles

of gas are there? (R=.0821L atm/mol K)

Answer 1

Answer: The number of moles of gas present are 0.390 moles

Step-by-step explanation:

To calculate the number of moles of gas, we use the equation given by ideal gas which follows:

`PV=nRT`

where,

P = pressure of the gas = 0.868 atm

V = Volume of the gas = 11 L

T = Temperature of the gas =
`25^oC=[25+273]K=298K`

R = Gas constant =
`0.0821\text{ L. atm }mol^(-1)K^(-1)`

n = number of moles of gas = ?

Putting values in above equation, we get:

`0.868atm* 11L=n* 0.0821\text{ L. atm }mol^(-1)K^(-1)* 298K\\\\n=(0.868* 11)/(0.0821* 298)=0.390mol`

Hence, the number of moles of gas present are 0.390 moles