Question

A gas storage tank has a volume of 15 L when the temperature is 115 C and the pressure is 114 kPa. What is the new volume of the tank if the temperature drops to -8.0 C and the pressure drops to 250.0 kPa? *

Answer 1

Answer: The new volume of the tank is 4.67 L

Step-by-step explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1,V_1\text{ and }T_1` are the initial pressure, volume and temperature of the gas

`P_2,V_2\text{ and }T_2` are the final pressure, volume and temperature of the gas

We are given:

`P_1=114kPa\\V_1=15L\\T_1=115^oC=[115+273]K=388K\\P_2=250kPa\\V_2=?\\T_2=-8^oC=[-8+273]K=265K`

Putting values in above equation, we get:

`(114kPa* 15L)/(388K)=(250kPa* V_2)/(265K)\\\\V_2=(114* 15* 265)/(388* 250)=4.67L`

Hence, the new volume of the tank is 4.67 L