Answer:
The value of Discriminant is 0.
Explanation:
Given,
![f(x)=-4x^2+12x-9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5te7fgb676t89itepv689w25kxbkr3s2r7.png)
We need to find the value of discriminant.
And also we need to find the number of real zeros 'f(x)' have.
Solution,
We have given the quadratic equation;
![f(x)=-4x^2+12x-9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5te7fgb676t89itepv689w25kxbkr3s2r7.png)
where
![a = -4\\\\b = 10\\\\c = -8](https://img.qammunity.org/2021/formulas/mathematics/high-school/rxgbmha45mjvxuslp2suv6zbclkqa23jgn.png)
Now we will find the Discriminant.
Discriminant can be calculated by using the formula
.
Substituting the values we get;
![D=b^2 - 4ac = 12^2-4*(-4)*(-9)=144-144 =0](https://img.qammunity.org/2021/formulas/mathematics/high-school/26ujchv487vdb3lsgjq2h1mzz5l33cjm52.png)
Hence the value of Discriminant is 0.