Question

Calculate the number of moles of h2 produced from the reaction of 2.08 mil

Of Mg and 2.08 mil of HCL

Answer 1

Answer: The amount of hydrogen gas produced in the reaction is 1.04 moles

Step-by-step explanation:

We are given:

Moles of Mg = 2.08 moles

Moles of HCl = 2.08 moles

The chemical equation for the reaction of magnesium and HCl follows:

`Mg+2HCl\rightarrow MgCl_2+H_2`

By Stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of magnesium metal.

So, 2.08 moles of HCl will react with =
`(1)/(2)* 2.08=1.04mol` of magnesium metal.

As, given amount of magnesium metal is more than the required amount. So, it is considered as an excess reagent.

Thus, HCl is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of HCl produces 1 mole of hydrogen gas

So, 2.08 moles of HCl will produce =
`(1)/(2)* 2.08=1.04moles` of hydrogen gas

Hence, the amount of hydrogen gas produced in the reaction is 1.04 moles