Question

Two protons and two neutrons are released as a result of this reaction.

Superscript 222 subscript 86.Rn Right arrow superscript 218 subscript 84.Po + ?

Which particle is released?
one alpha particle
two beta particles
one alpha and one beta particle
one high-energy photon

Answer 1

The answer is A

Step-by-step explanation:

Answer 2

Answer: The particle released in the given reaction is one alpha particle

Step-by-step explanation:

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

`^(222)_(86)\textrm{Rn}\rightarrow ^A_Z\textrm{X}+^(218)_(84)\textrm{Po}`

• To calculate A:

Total mass on reactant side = total mass on product side

222 = A + 218

A = 4

• To calculate Z:

Total atomic number on reactant side = total atomic number on product side

86 = Z + 84

Z = 2

The isotopic symbol of unknown element is
`_(2)^(4)\textrm{He}`. Another name of helium atom is alpha particle.

Hence, the particle released in the given reaction is one alpha particle