Question

a scooter has a mass of 250 kg. a constant force is exerted on it for 6.0 seconds. during the time the force is exerted, the scooter increases its speed from 6 meters per second to 28 meters per second what is the magnitude of the force exerted on the scooter

Answer 1

916.7N

Step-by-step explanation:

Force exeeted follows Newton's second law of motion hence is equal to the product of mass and acceleration, ma

The first step involves finding acceleration

Acceleration is the rate of change of velocity ler unit time, expressed as

`a==\frac {\triangle v}{t}=\frac {v-u}{t}`

Where a is acceleration, t is time, v and u represent final and initial velocities respectively.

Substituting this back into Force=ma

`F=m\frac {v-u}{t}`

Substititing 250 kg for m, 28 m/s for v and 6 m/s for u, 6 s for t then

`F=250\frac {28-6}{6}=916.6666666667N\\F\approx 916.7N`