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A boat travels between two riverside cities, A and B, located 21 miles apart. The river flows in the direction from A to B at 2 mph. The boat takes a total of 10 hours to make a round trip from A to B and back to A again. How long does it take the boat to make the one-way trip from A to B if the boats speed remailer constant relative to the speed of the river in each direction

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Answer:

The time taken by the boat to make the one-way trip from A to B = 3 hrs

Step-by-step explanation:

Distance between A & B = 21 mile

Velocity of river ( v ) = 2
(mi)/(hr)

Total time taken ( T )= 10 hours


T = (D)/(u - v) + (D)/(u +v)


10 = (21)/(u - 2) + (21)/(u + 2)


10 = (42 u)/(u^(2)-4 )


10 u^(2) - 42 u -40 = 0


u^(2) - 4.2 u - 4 = 0

By solving above equation we get

u = 5
(mi)/(hr)

The time taken by the boat to make the one-way trip from A to B


T = (D)/(u + v)


T = (21)/(5 + 2)

T = 3 hours

This is the time taken by the boat to make the one-way trip from A to B.

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