Question

If a photon has a frequency of 1.15 x 10 to the 15 power Hertz what is the energy of the photon given: Planck's constant is 6.63 x 10 to the negative 34 joule seconds

Answer 1

Step-by-step explanation:

Given:

Frequency, f = 1.15 × 10^15 Hz

Plancks constant, h = 6.63 × 10^-34 Js

Using the formula,

Energy, E = h × f

Inputting values,

Energy, E = 1.15 × 10^15 × 6.63 × 10^-34

= 7.6245 × 10^-19 J

Energy of the photon , E = 7.6245 × 10^-19 J.

Answer 2

7.62 x
`10^(-19)` J

Step-by-step explanation:

Given:

frequency 'f'= 1.15 x
`10^(15)` Hz

Planck's constant 'h'= 6.63x
`10^(-34)` Js

Energy of photon can be calculated by the formula:

E= hf

Where,

E= energy of photon

f= frequency of photon

h= Planck's constant

Putting the given values in the formula

E= 6.63x
`10^(-34)` x 1.15 x
`10^(15)`

E= 7.62 x
`10^(-19)` J

Therefore, the energy of photon is 7.62 x
`10^(-19)` J