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A golf ball is hit from a hill, and its height can be modeled by h(t)= -16 + 32t + 48, where he is the

height in feet and is the time in seconds. How long will it take for the ball to reach 64 feet.

1 Answer

1 vote

Answer:

1 second

Explanation:

We assume your model is intended to be ...

h(t) = -16t^2 +32t +48

Setting this equal to 64, we can find t ...

64 = -16t^2 +32t +48

t^2 -2t +1 = 0 . . . . . . subtract 64 and divide by -16

(t -1)^2 = 0 . . . . . . . . factor the square

t = 1 . . . . . . . . . . . . . the only solution

It will take the ball 1 second to reach a height of 64 feet.

A golf ball is hit from a hill, and its height can be modeled by h(t)= -16 + 32t + 48, where-example-1
User Ellen S
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