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41 votes
41 votes
In how many years will 600$ double itself at 10% simple interest?​

User Jurgen Camilleri
by
3.0k points

2 Answers

4 votes
4 votes

Answer:

10years

Explanation:

100%+100%=double

100/10=10 years to reach 100% so after ten years you will have 200%/double

User Hermannk
by
2.4k points
10 votes
10 votes


\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\ \\


\\ \large \purple{ \sf{Given→}} \\

  • P (Principal) → 600$
  • R (the annual rate) → 10% ,0.1

nd

  • Time → years let be x


\sf{A = 2P} \\ \sf{A = 2 * 600} \\ \sf{ A =\:1200} \\ \sf{cuz \: future \: value \: since \: the \: 600 \: will \: double \: itself}


\blue{\rule{70mm}{2.2pt}}


\\ \large \purple { \sf{Formula \: used→}} \\ \\ \rm{A = P(1 + r * t)}


\blue{\rule{70mm}{2.2pt}}

Substituting values


\rm{1200 = 600(1 + 0.1 * x)} \\ \\ \rm{600(1 + 0.1 * x) = 1200} \\ \\ \rm{1 + 0.1 * x = (1200)/(600) } \\ \\ \rm{ 1 + 0.1 * x = \cancel (1200)/(600) } \\ \\ \rm{1 + 0.1 * x = 2} \\ \\ \rm{0.1 * x = 2 - 1} \\ \\ \rm{x = 1 * (10)/(1) } \\ \\ \rm{x =10 }


\underline{\underline{\rule{70mm}{2.2pt}}}
\sf{\:мѕнαcкεя\: ♪...}

User Richard Read
by
2.9k points