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A mixture of CO(g) and H2(g) is pumped into a previously evacuated 2.0 L reaction vessel. The total pressure of the reaction system is 1.2 atm at equilibrium. What will be the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 L at constant temperature

User Nelga
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Answer:

The total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 L at constant temperature = 2.4 atm

Step-by-step explanation:

Total pressure of the system (P₁) = 1.2 atm at equilibrium

Volume (V₁) = 2.0 lit

If the volume of the reaction vessel is reduced to (V₂)= 1.0 lit

Pressure (P₂) ?

At constant temperature using Boyle's law

p₁v₁ = p₂v₂


or, P_(2)= (P_(1)V_(1) )/(V_(2) ) = (1.2 X2.0)/(1.0)=2.4 atm

Total pressure at equilibrium is equal to 2.4 atm.

User Running Buffalo
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