Question

A toy car, with mass of 6 Kg, is pushed with a force of 10 N. If the toy car is in the grass with a coefficient of friction of 0.1 then what is the acceleration?

How far does it get pushed in 10 s?

Answer 1

Fy=ma

Fn-mg=ma
Fn-6(10)=6a
Fn=6a+60

Fx=ma

10-Ff=ma
10-(Fn)(0.1)=6a
0.1Fn=-6a+10
Fn=-6a+10/0.1

(substitute)
-6a+10/0.1=6a+60
-6a+10=0.6a+6
-6.6a=-4
a≈0.61m/s^2

Use Kinematics to find x in 10s

x=Vt+1/2at^2
x=0+1/2(0.61)(10)^2
x≈30.3m

I hate physics :p hope this is accurate