Question

A long straight wire carries a current of 66 A. An electron, traveling at 1.0 ✕ 107 m/s, is 3.0 cm from the wire. What is the magnitude of the magnetic force on the electron if the electron velocity is directed as follows?

Answer 1

`7.04* 10^(-16) N`

Step-by-step explanation:

We are given that

Current,I=66 A

Speed,v=
`1.0* 10^7 m/s`

d=3 cm=
`(3)/(100)=0.03 m`

1 m=100 cm

We have to find the magnitude of the magnetic force on the electron if the electron velocity is directed as follows.

Magnetic field,B=
`(2\mu_0 I)/(4\pi d)`

`(\mu_0)/(4\pi)=10^(-7)`

Substitute the values

`B=(2* 10^(-7)* 66)/((0.03))=4.4* 10^(-4) T`

q=
`1.6* 10^(-19) C`

`F=qVB=1.6* 10^(-19)* 1* 10^7* 4.4* 10^(-4)=7.04* 10^(-16) N`