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What are the x-intercepts of the graph of y = -x2 - 6x + 40?

What are the x-intercepts of the graph of y = -x2 - 6x + 40?-example-1

2 Answers

1 vote

Answer:i think its 21

Explanation:

User Asraf
by
5.6k points
5 votes

Answer:

x=-10 x=4

Explanation:

y = -x^2 - 6x + 40

To find the x intercepts set y =0 and solve for x

0 = -x^2 - 6x + 40

Divide by -1

0 = x^2 + 6x - 40

What two numbers multiply to -40 and add to 6

10*-4 = -40

10 -4 = 6

(x+10) (x-4) =0

Using the zero product property

x+10 =0 x-4=0

x+10-10=0-10 x-4+4=0+4

x=-10 x=4

User William Pietri
by
5.7k points
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