Question

Solve the system of equations.

\begin{aligned} &3y+10x - 54=0 \\\\ &5y-2x-34=0 \end{aligned}

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3y+10x−54=0

5y−2x−34=0

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Answer 1

x= 0

y= -3

Explanation:

i got it

Answer 2

The answer is
`x=3` and
`y=8.`

Explanation:

Given:

3y+10x−54=0

5y−2x−34=0

Now, to solve the system of equations:

`3y+10x-54=0\\\\3y+10x=54\ \ \ ......(1)`

`5y-2x-34=0\\\\5y-2x=34\ \ \ \ ........(2)`

So, to multiply the equation (2) by 5 we get:

`25y-10x=170\ \ \ ...(2)`

Now, to solve the equations by adding both the equations (1) and (2):

`3y+10x+(25y-10x)=170+54\\\\3y+10x+25y-10x=224\\\\28y=224`

Then, dividing both sides by 28 we get:

`y=8.`

Now, substituting the value of
`y` in equation (1):

`3y+10x=54\\\\3(8)+10x=54\\\\3* 8+10x=54\\\\24+10x=54`

Subtracting both sides by 24 we get:

`10x=30`

Dividing both sides by 10 we get:

`x=3.`

Therefore, the answer is
`x=3` and
`y=8.`