Question

En un m.A.S. La amplitud tiene un valor de 10 centimetros y el periodo es de 2 segundos calcular el valor de la velocidad de 0.8 y 1.4 segundos de haberse iniciado el movimiento

Answer 1

v1=18.46m/s

v2=29.8cm/s

Step-by-step explanation:

We know that

`A=10cm\\T=2s`

the equation of the motion is

`x=Acos(\omega t)\\`

we can calculate w by using

`\omega=(2\pi)/(T)=(2\pi)/(2)=\pi`

Hence, we have that

`x=10cm*cos(\pi t)\\`

the speed will be

`v=-\omega*Asin(\omega t)\\|v(0.8)|=|\pi*10cm*sin(\pi *0.8)|=18.46(cm)/(s)\\|v(1.4)|=|\pi*10cm*sin(\pi *1.4)|=29.8(cm)/(s)`

hope this helps!