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A shopper is standing on level ground 800 feet from the base of a 250 foot tall department store the shopper looks up and sees a flag on the stores roof to the nearest degree what is the angle of elevation to the top of the building from the point on the ground where the shopper is standing?

User Slier
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Answer:

The elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°

Explanation:

From the ΔABC

AB = height of the building = 250 feet

BC = 800 ft

Angle of elevation =
\theta


\tan \theta = (AB)/(BC)


\tan \theta = (250)/(800)


\tan \theta = 0.3125


\theta = 17.35°

Therefore the elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°

A shopper is standing on level ground 800 feet from the base of a 250 foot tall department-example-1
User Morfidon
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