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A survey for brand recognition is done and it is determined that 68% of consumers have heard of Dull Computer Company. A survey of 800 randomly selected consumers is to be conducted. For such groups of 800, would it be unusual to get 634 consumers who recognize the Dull Computer Company name?

1 Answer

3 votes

Answer:

yes , it would be unusual to get 634 consumers who recognize the Dull Computer Company name .

Explanation:

Given -

A survey for brand recognition is done and it is determined that 68% of consumers have heard of Dull Computer Company.

The probability of success is ( p ) =
68\% = .68

The probability of failure is ( q ) = 1 - p =.32

Sample size (n) = 800

mean
\mathbf{(\\u ) = n* p}

=
800*0.68

= 544

Standard deviation
(\sigma) =
โˆš(n* p* q)

=
โˆš(544* .32)

= 13.2

Maximum usual values =
\\u + 2s

=
544 + 2*13.2

= 570.4

634 is more than 2 standard deviation above the mean, it would be unusual to get 634 consumers who recognize the Dull Computer Company name

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