Answer:
630 MP3 players are likely to be defective.
Explanation:
Given:
A shipment to a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 are defective.
Now, to find the MP3 players which are likely to be defective.
Let the defective MP3 players be
![x.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mmi228653dkvma4dszwy75q6dvkduzr4zg.png)
Total MP3 players = 4500.
In sample of 50 MP3 players 7 are defective.
Now, setting the proportion:
If, 50 is equivalent to 7.
Then, 4500 is equivalent to
![x.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mmi228653dkvma4dszwy75q6dvkduzr4zg.png)
Now, to solve using cross multiplication method:
![(50)/(7) =(4500)/(x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/2pkz4s0ruikw0iq68awweto8q6kr8zc348.png)
By cross multiplying we get:
![50x=31500](https://img.qammunity.org/2021/formulas/mathematics/high-school/cdrb56g9yb8h587194cmlwfojdhbjk7ryu.png)
Dividing both sides by 50 we get:
![x=630.](https://img.qammunity.org/2021/formulas/mathematics/high-school/380en4q6uj5qlft09nbyzzb61yjh7u3lo2.png)
Therefore, 630 MP3 players are likely to be defective.