Question

What is the diameter of a sphere with a volume of 4397\text{ m}^3,4397 m

3
, to the nearest tenth of a meter?

Answer 1

the diameter of a sphere is
`20.3m` .

Step-by-step explanation:

Here we have , a sphere with a volume of 4397 m^3 . We need to find the diameter of sphere . Let's find out:

We know that , Volume of sphere is given by formula as :

⇒
`Volume =(4)/(3)\pi r^3` .......(1)

According to question we have following parameters as :

`Volume = 4397m^3\\Radius = (Diameter)/(2)`

Putting these values in we get:

⇒
`Volume =(4)/(3)\pi r^3`

⇒
`4397 =(4)/(3)\pi ((D)/(2)) ^3`

⇒
`4397 =(4)/(3)\pi ((D^3)/(8))`

⇒
`4397 =\pi ((D^3)/(6))`

⇒
`D^3 =6 ((4397)/(\pi))`

⇒
`D^3 =6 ((4397)/(3.14))`

⇒
`D^3 =8402`

⇒
`D =\sqrt[3]{ 8402}`

⇒
`D =20.3m`

Therefore , the diameter of a sphere is
`20.3m` .

Answer 2

The diameter of a sphere is 20.32 m

Step-by-step explanation:

Given:

Volume of the sphere, V = 4397m³

Diameter, D = ?

We know,

Volume of the sphere =
`(4)/(3) \pi r^3`

Where,

r = radius of the sphere

On substituting the value in the formula we get:

`4397 = (4)/(3) \pi (r)^3\\\\r^3 = (4397 X 3)/(4\pi ) \\\\r^3 = 1049.7 m^3\\\\r = 10.16m`

Diameter = 2 X radius

D = 2 X 10.16 m

D = 20.32 m

Therefore, the diameter of a sphere is 20.32 m