Question

For an ideal gas under constant volume, if the pressure is tripled, what happens to the Kelvin temperature?

Answer 1

Increase pressure 3X => increase Temperature 3X

Step-by-step explanation:

Gay-Lussac Law => T ∝ P => T =kP => Empirical Relationship => T₁/P₁ = T₂/P₂

=> T₂ = T₁P₂/P₁

Given P₂ = 3P₁ => T₂ = T₁(3P₁)/P₁ = 3T₁