Answer / Explanation:
The question is incomplete as the beam was not given. However, kindly find the diagram of the beam below:
Solution:
Referring back to the beam, we have:
I = 1 / 12 ( 1 ) (4)³ + 2 [ 1 / 12 ( 4 ) (1)³ + 4 (1)(2.5)² ]
= 56 cm⁴
τ₁ = vq / it = 5 ( 2.75 )(4)(0.5) / (56)(4) = 1.72mpa
τ₂⁺ = vq / it = 5 (2.5)(4)(1) / (56)(4) = 3.125 mpa
τ₂⁻ = vq / it = 5 (2.5)(4)(1) / (56)(1) = 12.5 mpa
τ₃ = vq / it = 5 (2.5)(4)(1) + (1.75)( 1) (0.5) / (56)(1) = 13.6 mpa
τ₄ = vq / it = 5 (2.5)(4)(1) + (1.5)(1)(1) / (56) (1)
τmax = vq / it = 5 (2.5)(4)(1) + (1.25)(1)(1.5) / (56)(1) = 14.4 mpa