Question

You are holding a kite string in your hand. The angle of elevation from your hand to the kite is 44∘ and the distance to the kite is 250 feet. Your hand is 5 feet above the ground. How high is the kite? Round your answer to the nearest tenth of a foot.

Answer 1

178.7 ft

Explanation:

You are holding a kite string in your hand. The angle of elevation from your hand to the kite is $44\degree$ and the distance to the kite is 250 feet. Your hand is 5 feet above the ground. How high is the kite? Round your answer to the nearest tenth of a foot.

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Answer 2

The height of the kite is equal to
`178.7\ ft`

Explanation:

see the attached figure to better understand the problem

The point A is your hand and point C is the kite

we know that

In the right triangle BCD

`sin(44^o)=(CD)/(BC)` ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values

`sin(44^o)=(CD)/(250)`

solve for CD

`CD=sin(44^o)(250)=173.7\ ft`

The height of the kite is equal to

`AB+CD=5+173.7=178.7\ ft`