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Balance the following equation:
KOH + H2SO4 ⇒ K2SO4 + H2O

User Lseeo
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Answer:

2KOH(aq) + H2SO4(aq) ⇒ K2SO4(aq) + 2H2O(l)

Step-by-step explanation:

The reaction is a neutralization reaction since an acid, aqeous H2SO4 reacts completely with an appropriate amount of alkali, aqueous KOH to produce salt, aqueous K2SO4 and liquid water, H2O only.

2KOH(aq) + H2SO4(aq) ⇒ K2SO4(aq) + 2H2O(l)

Alkali + Acid → Salt + Water.

During this reaction, 2 moles of KOH neutralize 1 mole of H2SO4 to yield 1 mole of K2SO4 and 2 moles of H2O.

User Bohdan Nesteruk
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