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Calculate the mass of ZnCl2 produced by the reaction of 49.8 grams of H2. Zn + 2HCl ZnCl2 + H2

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Answer:

3300.85 g

Step-by-step explanation:

Given data:

Mass of ZnCl₂ produced = ?

Mass of H₂ produced = 49.8 g

Solution:

Chemical equation:

Zn + 2HCl → ZnCl₂ + H₂

Number of moles of H₂:

Number of moles = mass/molar mass

Number of moles = 49.8 g/ 2.056 g/mol

Number of moles = 24.22 mol

Now we will compare the moles of H₂ with ZnCl₂ form balance chemical equation.

H₂ : ZnCl₂

1 : 1

24.22 : 24.22

Mass of ZnCl₂:

Mass = number of moles × molar mass

Mass = 24.22 × 136.286 g/mol

Mass = 3300.85 g

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